Math, asked by 16presa0350, 4 months ago

tell this answer plss ​

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Answered by Anonymous
1

Answer:

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Step-by-step explanation:

Q3(a)

-2 \frac{1}{3} + 4 \frac{3}{5}\\\\\frac{-7}{3} + \frac{23}{5}\\\\taking\:\:LCM,\:\:we\:\:get\\\\= \frac{-7\times5}{3\times5} + \frac{23\times3}{5\times3}\\\\= \frac{-35}{15} + \frac{69}{15}\\\\= \frac{-35+69}{15}\\\\= \frac{34}{15}

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Q3 (b)

\frac{3}{7} \times \frac{-2}{5}\\\\=\frac{-6}{35}

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Q4

\frac{25 \times 5^2 \times t^8}{10^3 \times t^4}\\\\\\= \frac{25 \times 5^2 \times t^4}{10\times10\times10}\\\\\\= \frac{5\times 5\times5 \times t^4}{2\times10\times10}\\\\\\= \frac{5\times 1\times1 \times t^4}{2\times2\times2}\\\\\\= \frac{5\times t^4}{8}\\\\\\= \frac{5t^4}{8}

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