Physics, asked by Itzbuddy, 8 months ago

tell this fast dont spam it​

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Answers

Answered by Anonymous
5

Answer:

1) \sqrt{4}  {}^{ - 3} \\ (4 {}^{1 \div 2}  ) {}^{ - 3}  \\ 1 \div 4 {}^{3 \div 2}

2)(sqrt5)^-3(sqrt2)^-3

=>(1/sqrt4)^3(1/sqrt2)^3

=>(1/4^3/2)(1/2^3/2)

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Answered by rvkinage
1

Explanation:

Answer:

\begin{lgathered}1) \sqrt{4} {}^{ - 3} \\ (4 {}^{1 \div 2} ) {}^{ - 3} \\ 1 \div 4 {}^{3 \div 2}\end{lgathered}

1)

4

−3

(4

1÷2

)

−3

1÷4

3÷2

same answer

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