Biology, asked by aarchi82, 1 year ago

tell this please...............

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Answered by siddhartharao77
24

From figure:

Since OT is perpendicular bisector of PQ.

So, PM = QM = (1/2) PQ = 8 cm.

(i) In ΔOMP:

(OP)² = (PM)² + (OM)²

(10)² = (8)² + OM²

100 - 64 = OM²

36 = OM²

OM = 6 cm.

∴ Let TP = x.


(ii) In ΔPMT:

(TP)² = (PM)² + (MT)²

⇒ x² = 8² + MT²

⇒ x² = 64 + MT²


(iii) In ΔOPT:

(OT)² = (OP)² + (TP)²

⇒ (OT)² = 10² + x²

⇒ (OM + MT)² = 100 + x²

⇒ (6 + MT)² = 100 + x²

⇒ 36 + MT² + 2(6)(MT) = 100 + x²

⇒ 36 + MT² + 12MT = 100 + (64 + MT²)

⇒ 36 + MT² + 12MT - 100 - 64 - MT² = 0

⇒ -128 + 12MT = 0

⇒ MT = 128/12

Substitute in (ii), we get

⇒ x² = 64 + (128/12)²

⇒ x² = 64 + (16384/144)

⇒ x² = (9216 + 16384)/144

⇒ x² = (25600/144)

⇒ x = 160/12

⇒ x = 13.33 cm.


Therefore, TP = x = 13.33 cm.


Hope it helps!

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siddhartharao77: Great thanks!
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Anonymous: 200/100
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