Question

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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

secθ = (l² + 1)/2l

Step-by-step explanation:

Given: tanθ + secθ = l

⇒ tanθ = l - secθ

On squaring both sides, we get

⇒ tan²θ = (l - secθ)²

⇒ tan²θ = l² + sec²θ - 2lsecθ

∴ sec²θ - tan²θ = 1 (or) tan²θ = sec²θ - 1

⇒ sec²θ - 1 = l² + sec²θ - 2lsecθ

⇒ l² - 2lsecθ + 1 = 0

⇒ l² + 1 = 2lsecθ

⇒ secθ = (l² + 1)/2l

Hope it helps!