Question

tell this question.................​

Answer 1

Answer:

Step-by-step explanation:AE bisects ∠BAD

AF bisects ∠CAD

AE⊥ AF

∠CAF = ∠FAD (this is given)

∠BAE = ∠EAD (this is also given)

∠EAD + ∠FAD = 90° = ∠EAF (this is given too)

∠EAD + 1/2∠BAD and ∠FAD = 1/2 ∠CAD

1/2 ∠CAD + 1/2 ∠BAD= 90°

∠CAD + ∠BAD = 2x 90°

= 180°

The colinear point will lie on the straight line

and the straight line will make an angle of 180° on both sides.

∠CAD + ∠BAD

= ∠CAB = 180°

C,A, and B are colinear.

If there is any confusion please leave a comment below.

Answer 2

Answer:

it is proved...........

okkkk