Math, asked by 2004dayal, 11 months ago

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Answered by sibi61
3

Hi buddy

Here is your answer

Put the value of n as 1in equation1

Put the value of n as 1in equation1⇒S₁ = 3(1)² + 5(1)

Put the value of n as 1in equation1⇒S₁ = 3(1)² + 5(1)⇒S₁= 3 + 5

Put the value of n as 1in equation1⇒S₁ = 3(1)² + 5(1)⇒S₁= 3 + 5⇒T₁ = 8

Now, put value of n as 2

Now, put value of n as 2⇒S₂ = 3(2)² + 5(2)

Now, put value of n as 2⇒S₂ = 3(2)² + 5(2)⇒S₂ = 12 + 10

Now, put value of n as 2⇒S₂ = 3(2)² + 5(2)⇒S₂ = 12 + 10⇒S₂ = 22

So, T₁ + T₂ = 22

So, T₁ + T₂ = 22⇒8 + T₂ = 22

So, T₁ + T₂ = 22⇒8 + T₂ = 22⇒T₂ = 22 - 8

So, T₁ + T₂ = 22⇒8 + T₂ = 22⇒T₂ = 22 - 8⇒T₂ = 14First term(a) = 8

First term(a) = 8Common difference (d) = 14 - 8 = 6

First term(a) = 8Common difference (d) = 14 - 8 = 6ak(an) = 164

First term(a) = 8Common difference (d) = 14 - 8 = 6ak(an) = 164Using Formula⇒a + (k - 1)d = 164

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164⇒6k - 6 = 164 - 8

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164⇒6k - 6 = 164 - 8⇒6k = 164 + 6 - 8

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164⇒6k - 6 = 164 - 8⇒6k = 164 + 6 - 8⇒6k = 162

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164⇒6k - 6 = 164 - 8⇒6k = 164 + 6 - 8⇒6k = 162⇒k = 162/6

⇒a + (k - 1)d = 164⇒8 + (k - 1)6 = 164⇒6k - 6 = 164 - 8⇒6k = 164 + 6 - 8⇒6k = 162⇒k = 162/6⇒k = 27

Hope it help you

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#sibi ❤️

Answered by sbadiwal05
0

Answer:

hope it will help you. thanks

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