Question

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Class 12th Maths ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer

$\boxed{ \red{ \bf \: 4x – 3y – 4 = 0  }}$

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Explanation:

Given Equations are

• ❥︎ x – 2y + kz = 1 …. (i)
• ❥︎ 2x + y + z = 2 …....(ii)
• ❥︎ 3x – y – kz = 3 … (iii)

❥︎for locus of (x, y),

❥︎ adding equation (i) + (iii), we get

$:  \implies \tt \: x - 2y + kz + 3x - y - kz = 1 + 3$

$:  \implies \tt \: 4x - 3y = 4$

$:  \implies \tt \: 4x - 3y - 4 = 0$

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