Question

tell this r answer PLZ plzz plzz

Answer 1

hope its help u.........

Answer 2

$\textbf{ solution–}$

____________________________

$\frac{7x - 1}{4} - \frac{1}{3} \: (2x + \frac{x - 1}{2} ) = 6 \frac{1}{3} \\ \\ = > \frac{7x - 1}{4} - \frac{1}{3} ( \frac{4x + x - 1}{2} ) = \frac{19}{3} \\ \\ = > \frac{7x - 1} {4} - \frac{5x - 1}{6} = \frac{19}{3} \\ \\ = > \frac{3(7x - 1) - 2(5x - 1)}{12} = \frac{19}{3} \\ \\ = > \frac{21x - 3 - 10x + 2}{12} = \frac{19}{3} \\ \\ = > \frac{11x - 1}{4} = 19 \\ \\ = > 11x - 1 = 19 \times 4 \\ \\ = > 11x = 76 + 1 \\ \\ = > x = \frac{77}{11} \\ \\ = > x = 7$

$\textbf{ The value of x is 7}$

__________________________

$\huge\bold{Thanks}$