telll this one......
Answers
Answer:const:- divide the given figure into 3 parts- 2 semicircles(on the ends) and a rectangle in the center.
Step-by-step explanation:
Radius of inner semi-circle = =30 m ( as distance between parallel lines is 60m)
Circumference of inner semicircle =π.r=227×30=6607 m
The distance around the track along its inner edge=length of two inner parallel lines each equal to 106 m + circumference of two inner semicircles.
=106+106+6607+6607=28047 m
(ii)Area of the track = area of two rectangles formed in the track + area enclosed by the semi-circles ------------ (1)
Area of rectangle = length x breadth = 106 x width of track = 106 x 10=1060 m
⇒ Area of two rectangles=2 x 1060=2120 m --------------------------- (2)
Diameter of bigger semi-circle=60+width of track + width of track=60+10+10=80 m
⇒ Radius of bigger semi-circle =802=40 m
Area enclosed by left semi-circles=Area of bigger semi-circle-area of smaller semi-circle =π/2 x (r1)^2 − π/2 x (r2)^2
=π/2.(r1^2−r2^2)= π/2.(402−302)
=2214(1600−900)=1100 m^2
⇒ Area enclosed by left and right semi-circles=2 x 1100=2200 m ^2 ----------------------------------(3)
Putting (2) and (3) in (1), we get
Area of the track = area of two rectangles formed in the track + area enclosed by the semi-circles
=2120+2200= 4320 m^2
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