Physics, asked by abhi792533, 1 year ago

tema
A particle moves with velocity v=5t^2
acceleration at t= 3 sec.​

Answers

Answered by Anuragsingh573
1

dv/dt= a

a= 10t

a=10×3=30

Answered by mohan1508
1

acceelration = derivative of velocity

therefore

a \:  =  \: \frac{d}{dt} (5t {}^{2})

a = 10t

Put t = 3 sec

a = 10×3

a = 30m/s^2

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