Question

Temperative of water in a beaker is 50'c what is its value in Fahrenheit scale?
class 9th question​

Answer 1

Explanation:

Assumption : Assume no. heat loss to surrounding

So,

(ΔQ)

absorb

=(ΔQ)

given

∴T

F

=

m

1

s

1

+m

2

s

2

m

1

s

1

t

1

+m

2

s

2

t

2

=

45×4.2+50×0.39

45×4.2×323+50×0.39×291

=

208.5

66721.5

=320k

and

320k=320−273

∘

C

=47

∘

C

Answer 2

Answer:

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Explanation:

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