Question

Temperature 293 to 313 K reaction increase 4 times activation Energy is ??
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Answer 1

Answer:

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Answer 2

Answer:

=52.65

Explanation:

Sol:

log k1/k2=E of a/2.303R[T2-T1/T1×T2]

log4=E of a/2.303×8.314[313-293/293×313]

now, 0.6= E of a /19.14×20/91709

E of a=0.6×19.14×91709/20

E of a = 52.65 J

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