Temperature coefficient of resistance is 0.00100 per°C. Given the resistance of wire at 300k is 1 ohm. What will be the temperature in K when resistance become 2 ohm.
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Let the temperature at which the resistance is 2 ohms is T.
Now, at 300K , resistance is 1 ohm it is given.
So, the temperature difference will be T-300
therefore, 2=1(1+0.00125*(T-300))
so, 2 = 1 + 0.00125T - 0.375
so, 1.375 = 0,00125 T
hence T = 1.375/0.00125 - 1100 Kelvin. CLICK ON THANK YOU IF U LIKE
Now, at 300K , resistance is 1 ohm it is given.
So, the temperature difference will be T-300
therefore, 2=1(1+0.00125*(T-300))
so, 2 = 1 + 0.00125T - 0.375
so, 1.375 = 0,00125 T
hence T = 1.375/0.00125 - 1100 Kelvin. CLICK ON THANK YOU IF U LIKE
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