Question

Temperature inside an ideal refrigerator is 275K how much heat is delivered to room for every 1J of work done on working substance when room temperature is 315K

Answer 1

beta = T2/T1     /      1- T2 / T1 

   = T2 /  T2- T1

    = 273 /  315 - 273

     =   273 /  42  

beta = 11. 375

beta = Q2 / W

Q2 = BETA X W


Q2 = 11.375 X 1 J


Q2 = 11.375 J 


Q2 = amount of heat extracted per cycle from the cold reservoir at the temperature


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Answer 2

Answer:

By substituting values in , we get

Q1 = 12.375 J and Q2 = 11.375 J