Question

temperature of 5 mole of a gas is decreased by 2k at constant pressure . what is the work done by gas​

Answer 1

Answer:

A gas expends with temperatures according to the relation

V=KT power 2/3.where k is constant.

calculate work done when the

temperature changes by 60K. a-10R,b-30R,c-20R,d-40R

Answer 2

Work done by the gas is equal to 10 R.

• Heat released at constant pressure(Q) is equal to nCpΔT.
• The change in internal energy (ΔU) is equal to nCvΔT.
• According to first law of thermodynamics , the change in internal energy of a system is equal to the sum of the heat given to the system and work done (ΔU=Q=W)
• So, W=ΔU-Q

                 =nΔT(Cv-Cp)

                = 5×(-2)×(-R)

                =10R J