Physics, asked by shivampandey70041, 2 months ago

temperature of water is 60°C .calculate the temperature in °F


alfiaayoub3: amswer is 140°F. (60°C × 9/5) + 32 = 140°F
Anonymous: if you like my answer then mark me as brainlist please
Anonymous: I have given full step by step
Anonymous: please

Answers

Answered by alfiaayoub3
2

Answer:

Answer is 140°F as

(60°C × 9/5) + 32 = 140°F

Answered by Anonymous
5

60 °Celsius =140 °Fahrenheit

Solution:-

60C° = ?F°

Using formula=

 \frac{C}{5}  =  \frac{F - 32}{4}

C= Temp in °C

F=Temp in °F

Find:-

 =  >  \frac{60}{5}  =  \frac{F - 32}{9}

 =  >  \frac{60  \times 9}{5}

 =  >  \frac{540}{5}  = F - 32

108 = F - 32

F - 32 =  > F + 32

 =  > 108  + 32

 =  > 140°

60 °Celsius =140 °Fahrenheit

 =  > 60 °C =140 °F

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