Question

temperature1 = 25 c , temperature 2 = 10c , intial vol = 600 ml , final vol = 640 ml

calculate P2 ----- ??​

Answer 1

Applying Gas Law :

• P1V1 / T1 = P2V2 / T2

Putting value in Formula :

• Intial Temperature = 298°k

• Final Temperature = 283° k

• 760 × 600 / 298 = P2 × 640 / 283

• P2 = 760 × 600 × 283 / 640 × 298

• P2 = 676.6 mmHg

Hence :

• P2 = 676.6 mmHg

Answer 2

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Given, P^1

1

=760mmHg, V^1

=600mL

T^1

=273+25=298K

P^2 =? V^2

=640mL and T2

=273+10=283K

According to combined gas law equation,

T^1 P^1 V^1=T^2 P^2 V^2

or P^2

= V^2 T^1 /P^1 V^1 T^2

= (640mL)(298K)/(760mmHg)×(600mL)×(283K)

= 676.6mmHg