Temprature at which root mean square velocity of a molecule will be doubled than at 100c
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PV = (1/3)(Nmc^2) = RT
From which
T = (1/3)(Nmc^2)/R
Therefore,
T1/T2 = c1^2/c2^2 = (c1/c2)^2
T1 = 373 x 2^2 = 373 x 4 = 1492 K
Or 1219 C.
From which
T = (1/3)(Nmc^2)/R
Therefore,
T1/T2 = c1^2/c2^2 = (c1/c2)^2
T1 = 373 x 2^2 = 373 x 4 = 1492 K
Or 1219 C.
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