Physics, asked by osheajarrett2005, 5 months ago

Ten 1.5v cells, each having an internal resistance of 0.2 ohms , are connected in series to a load of 58 ohms . Determine (a) the current flowing in the circuit and (b) the p.d at the battery terminal

Answers

Answered by SiddharthAmrutkar
3

Answer:

If the circuit has 4ohms resistance total, then we have an external resistance of 3ohm (3 + 5(.2)=4). If you meant to ask about the total resistance with 4 ohms external to the batteries, then add the resistance of the batteries (4 + 5(.2) = 5) to get 5 ohms. If you are asking about the current running through the cirrcuit, (I'll assume we have 4 ohms plus battery internal resistances for the example's sake) simply divide total emf (aka voltage in most applications of the term) by the total resistance (5(2)÷5 = 2amps).

If you meant the question verbatim, then the question itself contains the answer (4 ohms connected to the batteries means that there is only 4 ohms external to the batteries).

Let me know if you meant something else. Ask your professor/instructor about the wording on the question. He may have half-assed an assignment or study guide, and has no clue about the botched question. Happened to me all the time when I had a research-addicted professor (or the one I swear was half-baked when he lectured; he lectured well, though).

Answered by Anonymous
7

Total Resistance = 58 + 0.2 ohms = 58.2 ohms

(i) So Current =

 \frac{v}{r}

 =  \frac{10 \times 1.5}{58.2}

 = 0.258A

and that's the answer.

Hope it helps

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