ten bags of wheat flour contain the following weights of flour (in kg) 4.97,5.05,5.08,5.03.5.00,5.06,5.08,5.04,5.00,4.98.Find the probability that any of these bags chosen at random contains more than 5kg of flour
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Given weights of flour = 4.97 , 5.05 , 5.08 , 5.03 , 5.00 , 5.06 , 5.08 , 5.04 , 5.00 , 4.98
n(S) = 10
Let (E) be the event of getting a bag with more than 5kg flour
n(E) = 6
P(E) = n(E)/n(S) = 6/10 = 3/5
n(S) = 10
Let (E) be the event of getting a bag with more than 5kg flour
n(E) = 6
P(E) = n(E)/n(S) = 6/10 = 3/5
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Total number of bags = 10
No.bags contains more than 5 kg of flour = 6
Probability that bag chosen at random contains more than 5 kg of flour = No.bags contains more than 5 kg of flour / Total number of bags
= 6/10
=3/5
No.bags contains more than 5 kg of flour = 6
Probability that bag chosen at random contains more than 5 kg of flour = No.bags contains more than 5 kg of flour / Total number of bags
= 6/10
=3/5
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