Math, asked by div30, 1 year ago

Ten cards are numbered as 1, 2,3,4.........10 respectively both are kept in a box and mixed thoroughly.one card is chosen at random from the box what is the probability of (i) getting the number 8 (ii) getting the number less than 5 (iii) getting the number greater than 4(iv)getting a digit number

Answers

Answered by ReetChauhan1112
10
(i) 1/10
(ii) 4/10 = 2/5
(iii) 6/10 = 3/5
(iv) 9/10
Answered by Disha234
8
no.of favorable outcomes=10
i.no. 8 is written only on 1 card so its sample space is 1. thats why its probability is---->
 probability of getting the number 8 is 1/10
ii. sample space{1,2,3,4}
no.of possible outcomes=4
so, probabiltity=4/10
=2/5

iii.sample space={5,6,7,8,9,10}
no.of possible outcomes=6
probabiltity=6/10
=3/5
iv.probabitity=9/10.



div30: (i) wala explain kar do plz
Disha234: okk
ReetChauhan1112: digit number means the numbers with only on digit and in 1 to 10 there are 9 digit numbers
ReetChauhan1112: how the last answer is 1
Disha234: thanks
Disha234: sister
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