Ten different books are arranged on a shelf. Find the number of different ways in which this can
be done, if two specified books are (a) to be together, (b) not to be together.
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Answered by
1
Answer:
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Step-by-step explanation:
Number of books =10
Total number of ways =10!
Given pair of books to be together considering them as one
total sets =9
Number of ways of arranging them =9!ways
Those two books can be arranged in 2!
Total ways that the pair of books is together
⇒9!×2!
Number of ways that are not together
⇒10!−9!×2!
⇒9!(10−2)
⇒8×9!
Answered by
0
Answer:
Number of books =10
Total number of ways =10!
Given pair of books to be together considering them as one
total sets =9
Number of ways of arranging them =9!ways
Those two books can be arranged in 2!
Total ways that the pair of books is together
⇒9!×2!
Number of ways that are not together
⇒10!−9!×2!
⇒9!(10−2)
⇒8×9!
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