Math, asked by amaanjaved7828, 10 months ago

Ten girls form a circle. Each one thinks of a number and whispers it to the two neighbors adjacent to her in the circle. Then each person computes and announced the average of the numbers she had heard from her 2 neighbors. The number announced by the girls were 44, 12, 23, 27, 40, 46, 56, 61, 69 and 36. What was the number picked by the person who announced the average as 56

Answers

Answered by rishika79
1

Answer:

Step-by-step explanation:

ans 56

let a b c d e f g h i j are in circle

now a+c=2*12=24

c+e=54

e+g=92

g+i=122

i+a=72

from the options if u take g=56

only then these equations will be satisfied

Hope it helps you...

Answered by Pratham2508
0

Answer:

The question is solved by using the hit and trial method where the only possible solution for the satisfaction of all situations is:-

Assume the 10 individuals as a,b,c,d,e,f,g,h,i,j are standing in a circle.

On the basis of the number announced by the girls we form equations like

  • a+c=2*12=24
  • c+e=54
  • e+g=92
  • g+i=122
  • i+a=72

This implies that G is 56 which is the girl we were finding and the number she picked was 56 as well.

Using this the equation can get satisfied

#SPJ3

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