Ten gram of an alloy of metals A and B contains 7.5 gm of metal A and the rest metal B.find the ratio between : (i) the weight of the metals A and B in the alloy (ii) the weight of metal B and the weight of an alloy
Answers
Answered by
150
(i) weight of metal B = ( 10 - 7.5 ) g
= 2.5 g
Ratio :-
weight of metal A : weight of metal B
=> 7.5 : 2.5
=> 3 : 1
(i) answer = 3:1
(ii)
weight of metal B = 2.5 g
weight of alloy. = 10 g
Ratio :-
2.5 : 10
=> 1 : 4
(ii) answer = 1:4
= 2.5 g
Ratio :-
weight of metal A : weight of metal B
=> 7.5 : 2.5
=> 3 : 1
(i) answer = 3:1
(ii)
weight of metal B = 2.5 g
weight of alloy. = 10 g
Ratio :-
2.5 : 10
=> 1 : 4
(ii) answer = 1:4
Answered by
5
Answer:
We know that
Total weight of A and B metals = 10 gm A weight - 7.5 gm B weight
So we get
= 10 – 7.5
= 2.5 gm
Ratio between the weight of metal B and the weight of the alloy = 2.5: 10
It can be written as
=1025:10
So we get
=25:100
=1:4
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