Ten litre of water per second is lifted from a well through 10
m and delivered with a velocity of 10 ms⁻¹. If
g = 10 ms⁻² , then the power of the motor is
(a) 1 kW (b) 1.5 kW
(c) 2 kW (d) 2.5 kW
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In this case, P=tmgh+21mv2
⇒P=tm[gh+2v2]
⇒P=110[10×10+210×10]W=1500W
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