Question

ten men working for 6 days for 10 hours each, finish 5/21 of a peace of work. how many men working at the same rate for the same number of hours each day, will be required to complete the remaining work in 8 days

Answer 1

Work do one = 5/21

Remaining work = 1- (5/2) = 16/21

5/21 of a work can be done in 6 days working

10 hours a day by = 10 m

1 work can be done in 6 days working 10 hours a day by = (10 × 21)/5

1 work can be done in 1 day working 10 hours day by = (10 × 21 × 6)/5 men

16/21 work can be done in 8 days working 10 hours a day by = (10 × 21 × 6 × 16)/(5 × 21 × 8) = 24 men

Answer 2

Answer:

24

Step-by-step explanation:

Lets first find the number of working hours required to complete   5/21  of the work.

M = number of men

D = number of days

H = number of hours worked per day

N = work done

MDH = N

10 x 6 x 10 = 5/21

Let the total number of hours required to complete the work be x then

x = 5/21 / 600

x = 600 x 21/5

x = 2520 hrs

So, the remaining work is 16/21 x

=16/21 x 2520

= 1920 hrs req. to complete remaining work

Now, MDH = N = 1920

M X 8 X 10 = 1920

M = 1920 / 80

M = 24

Hope it helps...