Question

Ten one rupee coins are put on top of each other on a table. Each coin has a mass m. Give the magnitude and direction ofa. the force on the 7th coin (counted from the bottom) due to all the coins on its top.b. the force on the 7th coin by the 8th coinc. the reaction of 6th coin on the 7th coin

Answer 1

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# Answer-
a) 3mg
b) 3mg
c) 4mg

# Explaination-
a) Force on 7th coin from above coins-
Here, 3 coins are above 7th coin.
Net force = 3 × weight of 1 coin
Fnet = 3mg

b) Force on 7th coin by 8th coin -
Here, 7th coin is directly affected by 8th coin which is affected by 9th and 10th coin.
Net force = 3 × weight of 1 coin
Fnet = 3mg

c) Reaction of 6th coin on 7th coin-
Here, reaction force by 6th coin is equal to force on it by above coins.
There are 4 coins above 6th.
Net force = 4 × weight of 1 coin
Fnet = 4mg

Hope that helps you...