. Ten one rupee coins each of mass m are placed on the top of each other. If coins are counted
from the bottom then calculate the force exerted by 8
th coin on the 7th coin.
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Answer:
3mg or 30m. no of coins above 7th coin= 3
therefore force on 7th coin=3mg
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Weight of one coin = mg
Weight of three coins = 3mg
the force exerted on the 7th coin by the eighth coin is eqal to the force exerted by the three coins on its top, which is is 3mg. This force acts vertically downward.
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