Physics, asked by manirandhawa8696, 10 months ago

. Ten one rupee coins each of mass m are placed on the top of each other. If coins are counted

from the bottom then calculate the force exerted by 8

th coin on the 7th coin.​

Answers

Answered by bhattak9617
0

Weight of one coin = mg

Weight of three coins = 3mg

the force exerted on the 7th coin by the eighth coin is eqal to the force exerted by the three coins on its top, which is is 3mg. This force acts vertically downward.

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