Question

Ten's place digit of two-digit number is greater than the unit place digit by 7. If the sum of the digits i
the number, find number.​

Answer 1

Step-by-step explanation:

The number is a two digit number.

Let us assume, the unit place digit is X. So, tens place digit is (x+7).

Now,

The number is,

={10(X+7)}+X

=10X+70+X

=11X+70

Reversing the digits-

The Unit position is (X+7)

Tens position is X

So, the new number is

={10X+(X+7)

=11X+7

The sum of the two numbers is 66

Then, (11X+70)+(11X+7)=66

=>22X+77=66

=>2X+7=6

=>2X=6-7

=>X= -(1/2)= -0.5

So the unit digit is -0.5

The answer is, if the obtained number is reversed and the digit is 66, then it should be

11X+70

= -(11/2)+70

= 70-5.5

= 64.5