Math, asked by siddhizanwar, 1 year ago

ten soliders are standing in the circle in the order 1 to 10 number 1 has a riffle, he killes the next solider. that is., number 2 and gives the riffle to the next, that is, number3. this continnues until only 1 survives. which number solider will survive in the end?

Answers

Answered by GANland
0
the soldiers will survive will 1,3,5,7,9

sameeramuji: 9 IS GOING TO GIVE THE GUN TO 1 AND IT IS GOING TO KILL 3
FabFam1: 9 is going to kill 1
sameeramuji: THEN 1 IS GOING TO GIVE THE GUN TO 5 AND IT IS GOING TO KILL 7
sameeramuji: THEN 5 WILL GIVE THE GUN TO 9 AND IT IS GOING TO KILL 1
sameeramuji: THE NINE WILLGIVE THE GUN TO FIVE IT IS GOING TO KILL 9
sameeramuji: SO THE LAST SOLDIER STNDIND WILL BE 5
FabFam1: See, first,all the even numbers will die. Then the gun will be with 9. 9 will kill 1, and give gun to 3. 3 will kill 5, give gun to 7, 7 will kill 9, give gun to 3, and 3 will kill 7!
sameeramuji: AS NINE HAS ALREADY KILLED TEN IT CAN'T KILL AGAIN
FabFam1: Answer is 5, sorry I thought only 9 soldiers were there
sameeramuji: THANK YOU
Answered by Chetubetu
1
The 9th number soldier will survives in the end
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