Question

ten student are participating in a race . in how many way can the first three prizes be won?

Answer 1

as there are total 10 students and 3 prizes...

therefore ,by permutation,

10p3 = 10x9x8 = 720

so, there are 720 ways that first there prizes be won.

Answer 2

Answer:

720 ways

Step-by-step explanation:

Given :Ten student are participating in a race .

To Find :in how many way can the first three prizes be won?

Solution:

We will use permutation over here

Formula : $^nP_r=\frac{n!}{(n-r)!}$

n = 10

r = 3

Substitute the values in the formula :

$^{10}P_{3}=\frac{10!}{(10-3)!}$

$^{10}P_{3}=720$

Hence the first three prizes can be won in 720 ways .