Ten year ago a man was 8 times as old as his son make linear equation
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Let the son's age be x years and man's age be y years
Son's age 10 years ago = x - 10 years
Man's age 10 years ago = y - 10 years
According to the question--
y - 10 = 8( x - 10)
y - 10 = 8x - 80
y - 8x = - 70
8x - y = 70
Therefore the required linear equation is 8x - y = 70
Son's age 10 years ago = x - 10 years
Man's age 10 years ago = y - 10 years
According to the question--
y - 10 = 8( x - 10)
y - 10 = 8x - 80
y - 8x = - 70
8x - y = 70
Therefore the required linear equation is 8x - y = 70
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