Question

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be find their present age

Answer 1

father's age = 34 years
and
son's age = 12 years

Answer 2

Answer:

Step-by-step explanation:

Given :-

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be.

To Find :-

Their ages.

Solution :-

Let the age of the son before 10 years be x

And age of the father before 10 years be 12x

10 years hence,

2(x + 10 + 10) = (12x + 10 + 10)

⇒ 2x + 40 = 12x + 20

⇒ 10x = 20  

⇒ x = 20/10

⇒ x = 2  

Age of son at present = x + 10 = 2 + 10 = 12

Age of the father at present = 12x + 10 = 24 + 10 = 34 years.