Question

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be. Find their present age.​

Answer 1

Answer:

After 10 years, father's age will be (x+10) years and son's age will be (y + 10) years. Also again from the question it's given as, Before 10 years, the age of father was (x - 10) years and the age of son was (y - 10) years. Hence, the present age of father is 34 years and the present age of the son is 12 years.

Step-by-step explanation:

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