Math, asked by SHIVAMDHASMANA, 6 hours ago

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be. Find their present age.

Koi hai? ​

Answers

Answered by itznakhrebaaz
9

Answer:

After 10 years, father's age will be (x+10) years and son's age will be (y + 10) years. Also again from the question it's given as, Before 10 years, the age of father was (x – 10) years and the age of son was (y – 10) years. Hence, the present age of father is 34 years and the present age of the son is 12 years.

nhi koi nhi hai sab tapak gaye xd..

itznakrebaaz

Answered by XxItzAdyashaxX
2

Answer:

After 10 years, father's age will be (x+10) years.

and son's age will be (y + 10) years.

Also again from the question

it's given as,

Before 10 years, the age of father was (x – 10) years.

and the age of son was (y – 10) years.

Hence, the present age of father is 34 years and the present age of the son is 12 years.

Ello.. ✌

Hai na mein hnu....

Adyasha here

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