Ten year later A will be twice as old as B and five years ago A was three times as old as B.What are there present ages?
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Answer:
A = 50 years and B = 20 years
Step-by-step explanation:
Let the present age of A be = x years
and the present age of B be = y years
Ten years later,
A's age will be = (x+10) years
B's age will be = (y+10) years
It is given that,
x+10 = 2y + 20
x - 2y = 10.....................(1)
Five years ago,
A's age was = (x-5) years
B's age was = (y-5) years
It is given that,
x-5 = 3y - 15
x - 3y = -10........................(2)
On solving (1) and (2) using elimination method, we get,
y = 20 years
x = 50 years
Hence, A's age present age is 50 years and B's present age is 20 years.
Hope it helps you....
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