Question

Ten years ago, A age was half of B age. If the ratio of their age is 3:4, what will be the sum of their present age

Answer 1

Let their present ages be 3x and 4x
Ten years ago their ages were 3x-10 and 4x-10
Therefore, (3x -10)=1/2(4x-10)
=>(3x-10) = 4x * 1/2 - 10*1/2
=>3x-10 = 2x*1-5
=>3x-10=2x-5
=> 3x -2x = -5 +10
=> x = 5

Therefore 3*5=15 and 4*5=20
And 15 + 20=35

Answer 2

answer is 35

hope it helps you.......