Math, asked by rajeshraoshabje, 8 months ago

Ten years ago a father was six times as old as his daughter. After ten years, he will be twice as
old as his daughter. Determine their present ages.

Answers

Answered by anish354

1

Answer:

After 10 years he will be twice as old as his daughter. Find their present age. F=6*15-50=40.

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