Question

Ten years ago, a father was twelve times as old as his son and ten years hence he will be
twice as old as his son will be then Form linear equations to represent the situation.​

Answer 1

Answer:

let the fathers age be x and sons age be y

The eqns are:

10 years ago,

x-10=12(y-10)

10 years hence,

x+10=2(y+10)

Answer 2

Step-by-step explanation:

Let father's age=x

Let son's age=y

according to the question

(x-10)=12(y-10)

(x+10)=2(y+10)