Question

ten years ago, a's age was half of b's age. if the ratio of their present ages is 3:4 what will be the sum pf their present ages

Answer 1

Before  ten years

Let  the age  of  B be  = 2x

Age  of  A  = x

Present time(After  ten years)

Age  of  A = x+10

Age  of  B = 2x+10

According  to question,

Ratio of  ages  = 3:4

$\frac{x+10}{2x+10}=\frac{3}{4}\\\\4x+40=6x+30\\\\2x=10\\\\x=5$

Thus,

Present  Age  of  A  = x+10 = 5+10 = 15

Present  Age of  B = 2x + 10 = 2×5 + 10 = 20