Question

Ten years ago, A,s age was half of B,s age .If the ratio of their present ages is 3：4,what will be the sum of their present age

Answer 1

ten years ago

B's age=x

A's age=1/2 of x

a=b

1/2*x=x

1x=2x

A=1*10

=10x

B=10*2

=20x

Ratio =3:4

=a:b

a=10*3

=30

ten years ago=30-10

=20

A's present age =30

A's age 10 years back=20

b=20*4

=80

ten years ago = 80-10

=70

B's present age =80

B's age ten years ago =70