Question

Ten years ago A was half of B in age. If the ratio of their present ages is 3:4, what will be the sum of their present ages?
42 years
23 years
18 years
35 years​

Answer 1

Answer:

35

Step-by-step explanation:

Let A's age 10 years ago = x years.

Then, B's age 10 years ago = 2x years.

(x + 10) / (2x+ lO) = 3/4

=> x = 5.

So, the total of their present ages =(x + 10 + 2x + 10)

= (3x + 20) = 35 years.