Ten years ago a was half of b in age.if the ratio of their present ages is 3:4,what will be the total of their present ages?
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Let the present ages of a and b be 3x and 4x
Now (4x-10) = 2(3x-10)
Solve it
X = 15
So 15, 20 are their present ages
SUM 15+20 = 35
Now (4x-10) = 2(3x-10)
Solve it
X = 15
So 15, 20 are their present ages
SUM 15+20 = 35
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