Question

Ten years ago A was half of B's Age. If ratio of their present ages is 3:4 then what is the total of their
present ages?
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Answer 1

Answer:

your answer is this

Step-by-step explanation:

x-10=y-10/2

2(x-10)=(y-10)

2x-20=20-10

2x-y=10

2x=10+y

x/y=3/4

4x=3y

x=3y/4

2(3y+4)/2=10+y

3y/2=10+y

3y=2(10+y)

3y=20+2y

3y-2y=20

y=20

the age of B is 20year

x=3y/4

x=3*5

x=15

the age of a is=20year

Answer 2

Answer:

Step-by-step explanation:

Let, ten years ago,

B's age = x years

A's age = x/2 years

at present,

    (x/2 + 10)/(x + 10) = 3/4

=> 3(x + 10) = 4(x/2 + 10)

=> 3x + 30 = 4*x/2 + 40

=> 3x + 30 = 2x + 40

=> 3x - 2x = 40 - 30

=> x = 10

so, at present,

 A's age + B's age

=(x/2 + 10) + (x + 10)

= (10/2 + 10) + (10 + 10)

=((10+20)/2) + 20

=(30/2) + 20

= 15 + 20

=35 years