ten years ago age of father is 2 more than three times the age of son. three years later father's age will be 10 years more than twice the age of his son .find their present ages.
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Let father’s age be x & son’s age be y
By 1st condition:
3 + 3y = x (three plus three times age of son is father’s age)
By 2nd condition:
x + 3 = 2(y + 3) + 10 [here we are talking about 3 years hence. So 3 has to be added to their present ages, and then satisfy the condition]
So the final 2 equations are
x-3y = 3 … (1)
x-2y = 13 … (2)
Solving them we get
y = 10, x = 33
So the father’s present age is 33 and that of the son is 10.
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