Math, asked by nishi6057, 6 months ago

Ten years ago diva's age was half of namrata. if the ratio of today's their ages is 3:4, then the sum of their current age will be.​

Answers

Answered by Anonymous
0

Answer:

d - 10 = n/2

3:4::d:n

so,

4d = 3n

4d/3 = n

d - 10 = 4d/3* 1/2

d - 10 = 4d/6

d - 10 = 2d/3

d - 2d/3 = 10

(3d-2d)/3 = 10

d/3 = 10

d = 30  , n = 30/2 = 15

d = divya , n = namrata

Step-by-step explanation:

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Answered by nouman4181
0

Step-by-step explanation:

Let the present age of Divya and Namrata are 3x and 4x years respectively; then

According to question,

Ten years ago, Age of Divya = 3x - 10

Ten years ago, Age of Namrata = 4x - 10

Now According to question,

Ten years ago, the age of Divya was half of the age of Namrata

3x - 10 = (4x - 10)/2

⇒ 6x - 20 = 4x - 10

⇒ 2x =10

∴ x = 5

Hence, sum of their ages = 3x + 4x = 7x =7 x 5 = 35 years

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