Question

ten years ago father age is 3 times greater than his child. After 10 years father age will twice the childs age .Then what wilo the age of his child today​

Answer 1

Answer:

By solving simultaneously,

let the age of father be x and child be y,

then

x-10=3(y-10)--(1)

x+10=2(y+10)--(2)

=x-10=3y-30--(1)

=x+10=2y+20--(2)

=x-3y=-20--(1)

=x-2y=10

subtracting 1 from 2,

=-y=-30

y=30

substituting the value of x in equation 1 ,

x-3*30=-20

x=-20+90

x=70

The present age of father is 70 years and child is 30 years.

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Answer 2

• The present age of father = 30 yrs
• The present age of Child = 10 yrs

Step-by-step explanation:

Let,

• Father's present age be 'x'
• Child's present age be 'y'

According to the question, It is given that,

Ten years ago,

• $\sf{x\:=\:3y}$------- (1)

After 10 years,

• x would be $\sf{x\:+\:10}$ and
• y would be, $\sf{y\:+\:10}$

It is given that, father's age will twice the child's age,

$\implies\sf{x\:+\:10\:=\:2\:(y\:+\:10)}$

$\implies\sf{x\:+\:10\:=\:2y\:+\:20}$

Substituting 'x' value,

$\implies\sf{x\:+\:10\:=\:2y\:+\:20}$

$\implies\sf{3y\:+\:10\:=\:2y\:+\:20}$

$\implies\sf{3y\:-\:2y\:=20\:-\:10}$

$\implies\sf{y\:=\:10}$

Substituting 'y' value in (1),

$\implies\sf{x\:=\:3y}$

$\implies\sf{x\:=\:3\:\times\:10}$

$\implies\sf{x\:=\:30}$

Hence, The present age of father = 30 yrs and The present age of Child = 10 yrs.