Question

Ten years ago, Father's age was thrice as his son. The difference between thier age was 20 years. Find the present age of the son..​

Answer 1

Step-by-step explanation:

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+10)+10=2[(x+10)+10]

⇒3x+20=2x+40

⇒x=20

∴ Required ratio =(3x+10):(x+10)=70:30=7:3

Answer 2

Father Present Age = F

Son Present Age = S

• Ten years ago, Father's age was thrice as his son

F - 10 = 3(S - 10)

• Difference between their age was 20 years

F - S = 20

• Solving above Equation.

F - 10 = 3(S - 10)

20 + S - 10 = 3S - 30

S + 10 = 3S - 30

2S = 40

S = 20

Father Present Age = 40

Son Present Age = 20