Question

ten years ago father was 12 time as old as his son ahd 10 years hence he will be twice as old as his son find their present ages ​

Answer 1

Answer:

The present age of father is 34 years and son is 12 years.

Step-by-step explanation:

Let the father's present age be y years and the son's present age be x years.

It is provided that:

$y-10=12(x-10)\\y-10=12x-120\\12x-y=110...(i)$

$y+10=2(x+10)\\y+10=2x+20\\2x-y=-10...(ii)$

Solve equations (i) and (ii) simultaneously as follows:

$12x-y=110\\-2x+y=+10\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\10x=120\\x=12$

Compute the value of y as follows:

$2x-y=-10\\y=(2\times12)+10\\=24+10\\=34$

Thus, the present age of father is 34 years and son is 12 years.